Central Moments Overview

Central moments are statistical measures calculated around the mean (or any fixed point) rather than around zero. They describe various characteristics of a distribution’s shape.

The r-th central moment is defined as:

$$m_r = \frac{\sum(x_i - \bar{x})^r}{n}$$

where $\bar{x}$ is the mean and n is the number of observations.

The Four Key Central Moments

First Central Moment (m₁)

Always equals zero by definition:

$$m_1 = \frac{\sum(x_i - \bar{x})}{n} = 0$$

This is because the sum of deviations from the mean is always zero.

Second Central Moment (m₂)

Equals the variance:

$$m_2 = \frac{\sum(x_i - \bar{x})^2}{n} = \sigma^2$$

Property: Measures spread or dispersion around the mean

Third Central Moment (m₃)

Related to skewness:

$$m_3 = \frac{\sum(x_i - \bar{x})^3}{n}$$

Property: Measures asymmetry; used to calculate skewness coefficient

$$\text{Skewness} = \frac{m_3}{s^3}$$

Fourth Central Moment (m₄)

Related to kurtosis:

$$m_4 = \frac{\sum(x_i - \bar{x})^4}{n}$$

Property: Measures tailedness; used to calculate kurtosis

$$\text{Kurtosis} = \frac{m_4}{s^4}$$

Central Moments for Ungrouped Data

Example 1: Complete Calculation

Data: 12, 14, 16, 18, 20

Calculate all central moments.

Solution:

Step 1: Calculate mean

$$\bar{x} = \frac{12 + 14 + 16 + 18 + 20}{5} = \frac{80}{5} = 16$$

Step 2: Create deviation table

$x_i$ $(x_i - \bar{x})$ $(x_i - \bar{x})^2$ $(x_i - \bar{x})^3$ $(x_i - \bar{x})^4$
12 -4 16 -64 256
14 -2 4 -8 16
16 0 0 0 0
18 2 4 8 16
20 4 16 64 256
40 0 544

Step 3: Calculate central moments

$$m_1 = \frac{0}{5} = 0$$

$$m_2 = \frac{40}{5} = 8 \text{ (variance)}$$

$$m_3 = \frac{0}{5} = 0$$

$$m_4 = \frac{544}{5} = 108.8$$

Step 4: Calculate skewness and kurtosis

$$\text{Skewness} = \frac{m_3}{(\sqrt{m_2})^3} = \frac{0}{(2.83)^3} = 0$$

(Symmetric distribution)

$$\text{Kurtosis} = \frac{m_4}{(\sqrt{m_2})^4} = \frac{108.8}{(8)^2} = 1.7$$

$$\text{Excess Kurtosis} = 1.7 - 3 = -1.3$$

(Platykurtic - flatter than normal)

Example 2: Skewed Distribution

Data: 10, 15, 20, 25, 50

Calculate central moments.

Solution:

$$\bar{x} = \frac{120}{5} = 24$$

$x_i$ $(x_i - \bar{x})$ $(x_i - \bar{x})^2$ $(x_i - \bar{x})^3$ $(x_i - \bar{x})^4$
10 -14 196 -2,744 38,416
15 -9 81 -729 6,561
20 -4 16 -64 256
25 1 1 1 1
50 26 676 17,576 456,976
970 14,040 502,210

$$m_2 = \frac{970}{5} = 194$$

$$m_3 = \frac{14,040}{5} = 2,808$$

$$m_4 = \frac{502,210}{5} = 100,442$$

$$\text{Skewness} = \frac{2,808}{(13.93)^3} = 1.13$$ (Positively skewed)

Central Moments for Grouped Data

Formula

For grouped data:

$$m_r = \frac{\sum f_i(m_i - \bar{x})^r}{N}$$

where:

  • $f_i$ = frequency of class i
  • $m_i$ = midpoint of class i
  • $\bar{x}$ = mean
  • N = total frequency

Example: Grouped Data

Class Frequency Midpoint
0-10 5 5
10-20 12 15
20-30 18 25
30-40 10 35
40-50 5 45

Calculate central moments (assume mean = 23.5).

Solution:

Class $f$ $m_i$ $(m_i - \bar{x})$ $f(m_i - \bar{x})^2$ $f(m_i - \bar{x})^3$ $f(m_i - \bar{x})^4$
0-10 5 5 -18.5 1,711.25 -31,658.125 585,075.3
10-20 12 15 -8.5 867 -7,369.5 62,640.75
20-30 18 25 1.5 40.5 60.75 91.125
30-40 10 35 11.5 1,322.5 15,208.75 174,900.625
40-50 5 45 21.5 2,306.25 49,584.375 1,066,064.0625
N=50 6,247.5 25,826.25 1,888,771.875

$$m_2 = \frac{6,247.5}{50} = 124.95$$

$$m_3 = \frac{25,826.25}{50} = 516.525$$

$$m_4 = \frac{1,888,771.875}{50} = 37,775.44$$

Relationship Between Central Moments and Distribution Shape

Moment Property Interpretation
m₂ Variance Data spread around mean
m₃ Related to skewness Data asymmetry
m₄ Related to kurtosis Tail weight and peakedness

Central Moments vs. Raw Moments

Raw Moment: $$\mu_r’ = \frac{\sum x_i^r}{n}$$

Conversion Formula: $$m_r = \sum \binom{r}{k} (-1)^k \bar{x}^k \mu_{r-k}’$$

Central moments are more useful for statistical analysis because they’re invariant to location (translation).

Applications of Central Moments

  1. Distribution Characterization: Understanding shape properties
  2. Skewness Calculation: Measuring asymmetry
  3. Kurtosis Calculation: Measuring tailedness
  4. Statistical Tests: Basis for normality tests
  5. Moment Matching: Estimating parameters
  6. Risk Assessment: Analyzing financial returns

Properties of Central Moments

  1. m₁ = 0 (always)
  2. m₂ > 0 (always positive)
  3. m₃ = 0 for symmetric distributions
  4. m₄ ≥ m₂² (Cauchy-Schwarz inequality)
  5. Scale Property: If $y = cx$, then $m_r(y) = c^r m_r(x)$

Comparison: Symmetric vs. Skewed Data

Symmetric Distribution

  • $m_1 = 0$
  • $m_3 = 0$
  • Mean = Median = Mode

Right-Skewed Distribution

  • $m_1 = 0$
  • $m_3 > 0$ (positive)
  • Mean > Median > Mode
  • Longer tail on right

Left-Skewed Distribution

  • $m_1 = 0$
  • $m_3 < 0$ (negative)
  • Mean < Median < Mode
  • Longer tail on left

Practical Example: Quality Control

Manufacturing measurements (n = 100):

  • $m_2 = 2.5$ → SD = 1.58 (process spread)
  • $m_3 = 0.15$ → Slight positive skew (slight bias)
  • $m_4 = 18.2$ → Relatively high kurtosis (more variability)

Conclusion: Process slightly biased high with more extreme variations than normal.

Computational Notes

  • For large datasets, use computational formulas to reduce rounding errors
  • Center data (subtract mean) before calculations when possible
  • For grouped data, use class midpoints as representatives
  • Higher central moments are more sensitive to outliers

Limitations

  • Can be sensitive to extreme values
  • Interpretation becomes complex for moments beyond the fourth
  • Calculation can be computationally intensive for large datasets
  • Different assumptions needed for different distribution types